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Re: xsl 2.0 recursive functions and return value

2006-02-26 13:53:53
Michael Kay wrote:
how can i get the following to work:


<xsl:function name="r2c:hasTextContent" as="xs:boolean">
   <xsl:param name="node"/>
     <xsl:for-each select="$node/*">
       <xsl:choose>
         <!--ignore!-->
         <xsl:when test="r2c:isOutputNode(.)"/>
         <!--gotcha!-->
         <xsl:when test="r2c:isLeafNode(.)">
           <xsl:value-of select="true()"/>
         </xsl:when>

Use xsl:sequence here! xsl:value-of creates a text node. You're converting a
boolean to a string, wrapping the string in a text node, then because an
xs:boolean is required, the text node is atomized, and the string "true" is
converted back to a boolean.

of course. it was supposed to be a sequence, but old habits...

Try:

<xsl:function name="r2c:hasTextContent()" as="xs:boolean">
  <xsl:param name="node" as="node()"/>
  <xsl:sequence select="some $x in $node/*[not(r2c:isOutputNode(.)]
satisfies
     (r2c.isLeafNode($x) or r2c.hasTextContent($x))"/>
</xsl:function>

wow. quantifiers! cool. i hadn't yet noticed they exist.


please no more spoilers, your books on xsl2/xpath2 are scheduled to arrive on tuesday :-D


thanks a lot!

jörn


--
jörn nettingsmeier

home://germany/45128 essen/lortzingstr. 11/
http://spunk.dnsalias.org
phone://+49/201/491621

if you are a free (as in "free speech") software developer
and you happen to be travelling near my home, drop me a line
and come round for a free (as in "free beer") beer. :-D

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