If you have to output the same tree 10 times, then it's probably a good idea
to construct it in a variable and use xsl:copy-of each time you want to
output it. If you only have to output it twice, then recalculating it might
be faster. Only way to find out is to measure it.
Some processors might create a variable automatically. Saxon doesn't,
especially in the case of expressions that create new nodes, because there
are complicated rules about the identity of the nodes that are created.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Liron [mailto:magilam(_at_)netvision(_dot_)net(_dot_)il]
Sent: 22 February 2006 16:20
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Outputing the same value-of for different nodes
Hello,
I wanted to ask how to output the same value on different
nodes without
effecting performance. Here's an example:
original xml file:
<tree>
<son><value>something1</value></son>
<son><value>something2</value></son>
<son><value>something3</value></son>
</tree>
Lets assume I want to output something like this:
<tree>
<first>
<son><value>something1><position>1</position></value></son>
<son><value>something2><position>2</position></value></son>
<son><value>something3><position>3</position></value></son>
</first>
<second>
<son><value>something1><position>1</position></value></son>
<son><value>something2><position>2</position></value></son>
<son><value>something3><position>3</position></value></son>
</second>
</tree>
This is just an example so please don't question the need for
such an output
;)
In my xslt I'd probably use a xsl:for-each select="/tree/son"
and then
output the "value" node and "position()" under the "first"
node but would I
have to write a
"xsl:for-each" again only output it for the "second" node or
there's some
way of outputing the same value, lets say "position()", under
different
output nodes?
Thank you
Liron
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