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RE: Returning an element's position number

2006-02-16 09:07:34
Thanks so much - that did the trick!

Cindy Hunt
 

-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk] 
Sent: Thursday, February 16, 2006 10:21 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Returning an element's position number


see the recent thread (with the rather unhelpful tile "Re: [xsl] Stumped on 
XPath")

  The trick with doing cross references in XSLT is always generate the
  reference text _at the referenced node_ not on the referencing node.
  then you can easily get the same number in the reference and in the
  referenced heading. (Often by just calling a named template or special
  mode that just does the numbering.


so just have
<xsl:key name="l" match="legend" use="@id"/> then on your reference element do  
<xsl:for-each select="key('l',@link)">
                         <xsl:number/>
</xsl:for-each<

so that you generate the number on the <legend element even though it is output 
at the point of the reference.

David

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