Thanks so much - that did the trick!
Cindy Hunt
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: Thursday, February 16, 2006 10:21 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Returning an element's position number
see the recent thread (with the rather unhelpful tile "Re: [xsl] Stumped on
XPath")
The trick with doing cross references in XSLT is always generate the
reference text _at the referenced node_ not on the referencing node.
then you can easily get the same number in the reference and in the
referenced heading. (Often by just calling a named template or special
mode that just does the numbering.
so just have
<xsl:key name="l" match="legend" use="@id"/> then on your reference element do
<xsl:for-each select="key('l',@link)">
<xsl:number/>
</xsl:for-each<
so that you generate the number on the <legend element even though it is output
at the point of the reference.
David
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