I haven't studied the question closely but you probably want
footnote[(_at_)id=current()/@fnref]
Note that ./@fnref means the same as @fnref, so
footnote[(_at_)id=(_dot_)/@fnref]
looks for a footnote whose id and fnref attributes have the same value.
Following cross-references is often best done using keys: it's certainly
more efficient and many people say the code is clearer. Look up xsl:key.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Jiang, Peiyun
[mailto:Peiyun(_dot_)Jiang(_at_)nrc-cnrc(_dot_)gc(_dot_)ca]
Sent: 09 February 2006 16:20
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] help with select
I'm trying to made the following code work:
./footnote|//footnote[(_at_)id=(_dot_)/@fnref]
I want to select the child footnote element of author and any
footnote that its id attribute matches the fnref attribute of
the author.
In footnote[(_at_)id=(_dot_)/@fnref], is "." referring to author or to
footnote? How do you refer author?
Thanks.
Peiyun
<xsl:template match="author">
<!-- something here -->
<xsl:choose>
<xsl:when
test="count(./footnote|//footnote[(_at_)id=(_dot_)/@fnref]) = 1">
<xsl:apply-templates
select="./footnote|//footnote[(_at_)id=(_dot_)/@fnref]"/>
</xsl:when>
<xsl:when
test="count(./footnote|//footnote[(_at_)id=(_dot_)/@fnref]) > 1">
<xsl:for-each
select="./footnote|//footnote[(_at_)id=(_dot_)/@fnref]">
<xsl:choose>
<xsl:when test="position() = last()">
<xsl:apply-templates select="." />
</xsl:when>
<xsl:when test="position() != last()">
<xsl:apply-templates select="." />
<sup>,<xsl:text> </xsl:text></sup>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</xsl:when>
</xsl:choose>
<!-- some other things here -->
</xsl:template>
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