You may try something like this
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
<xsl:output method="text" />
<xsl:template match="/data">
<xsl:for-each select="items/date">
<xsl:sort select="translate(., '.', '')" order="descending"
data-type="number" />
<xsl:if test="position() = 1">
<xsl:value-of select="." />
</xsl:if>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
On 2/8/06, jeb501(_at_)sanmargroup(_dot_)com
<jeb501(_at_)sanmargroup(_dot_)com> wrote:
Hi all,
From the below XML file how to pick the late date from date node..
<?xml version="1.0" encoding="Windows-1252" standalone="yes" ?>
- <data>
- <items>
<ref>28834</ref>
<pdate>01.02.2006</pdate>
<qty>5</qty>
<clno>ax588</clno>
<date>01.02.2006</date>
<clrf>Normal 1</clrf>
<clno>bx588</clno>
<date>03.02.2006</date>
<clrf>Normal 2</clrf>
<clno>bx588</clno>
<date>06.02.2006</date>
<clrf>Normal 3</clrf>
</items>
</data>
Regards
Eugene
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