Re: Transform XML to DXL using XSLT

Hi,

Thanks Gurus for your help.
I am really new to XSL so gets stuck in simple problems.

How can I modify the xsl program given by Michael and Florent if the
Document A is
<eapqp:ItemList>
         <eapqp:Level>Level 1</eapqp:Level>
      <eapqp:PartNumber>987654321</eapqp:PartNumber>
</eapqp:ItemList>

I tried by changing the xslt by

<xsl:template match="eapqp:Level">
   <item name="Level"><text><xsl:value-of select="."/></item>
</xsl:template>

But it giving me error as illegal prefix.
Please suggest a solution.


Cheers,
Rob


On 3/2/06, Michael Kay <mike(_at_)saxonica(_dot_)com> wrote:

Now I am stuck with a new problem and I am not able to find
any solution for it.


If this is a new problem, then I wonder what problems you've been tackling
until now. This is about as classic a one-to-one transformation as they
come.


I want to use XSLT to transform XML file to DXL (Domino XML) file. Dxl
file is also a xml file used by Lotus Notes.
For example what could be the xslt for converting document A
into document B.


<xsl:template match="ItemList">
<documents>
  <document>
    <xsl:apply-templates/>
  </document>
</documents>
</xsl:template>

<xsl:template match="Level">
  <item name="Level"><text><xsl:value-of select="."/></item>
</xsl:template>

<xsl:template match="PartNumber">
  <item name="PartNumber"><text><xsl:value-of select="."/></item>
</xsl:template>

Michael Kay
http://www.saxonica.com/


Document A:

<ItemList>
        <Level>Level 1</Level>
        <PartNumber>987654321</PartNumber>
</ItemList>

Document B:

<documents>
    <document>
        <item name="Level"><text>Level 1</text></item>
        <item name="PartNumber"><text>987654321</text></item>
    </document>
</documents>

Thanks in advance.

Cheers,
Rob

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