Hi List!
<xsl:for-each
select="/tamino-result/Bs_Bauteil_Liste[(_at_)gebaeude_id=$gebId]/Brandwand_Liste
/Brandwand[funktion='Trennwand']">
<xsl:sort select="." order="ascending" data-type="text"/>
<xsl:variable name="ID" select="@ID" />
<xsl:variable name="bez" select="bezeichnung" />
<xsl:variable name="wand_ID" select="Wand_id_Liste/wand_id"/>
<xsl:variable name="bauteil_test" > <!-- Prüft, ob das Bauteil
im aktuellen Stockwerk Teil der Trennwand ist. Nur dann wird diese in den
Baum eingefügt. -->
<xsl:for-each
select="/tamino-result/Gebaeude[(_at_)ID=$gebId]/Stockwerk_Liste/Stockwerk[(_at_)ID=$s
tock_ID]//bauteil_id">
<xsl:if test="string(.) = string($wand_ID)">
<xsl:text>true</xsl:text>
</xsl:if>
</xsl:for-each>
</xsl:variable>
<xsl:if test="$bauteil_test = 'true'">
DO SOMETHING
</xsl:if>
</xsl:for-each>
The Element ?Trennwand? consists of several ?wand?-Elements with a wand_id.
These ?wand?-Elements are children of ?bauteil?-Elements with a bauteil_id.
So wand_id and bauteil_id are the same.
With the above code I want to test, if a Trennwand has a wand_id same as
the bauteil_id in a specific ?Stockwerk?. So I can find out, in which
?Stockwerk? the Trennwand is located.
The problem is, that these bauteil_ids exist several times in every
?stockwerk?.
Now, the code it self is working, but I have a problem with the variable
?bauteil_test?.
In my example the ?bauteil_id? exists three times in the ?Stockwerk?. So the
result of the variable is:
<xsl:variable name="bauteil_test" >truetruetrue</xsl:variable>
But what I want is:
<xsl:variable name="bauteil_test" >true</xsl:variable>
How can I do this??
I hope someone understood my problem.
Thanks,
Barthi
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--