Hi Jarno,
Thanks for the reply. Looks like I haven't included enough of the
snippet for you to give the right solution. The snippet is as follows:
<xsl:template match="@*">
<xsl:attribute name="{name(.)}">
<xsl:value-of select="."/>
<xsl:number count="*"/>
</xsl:attribute>
</xsl:template>
As you can see, the context node is an attribute node and Iam getting the
error,
Attribute nodes cannot be numbered.
Could you tell me the way to do this for attribute nodes.
cheers,
V.Omprakash
Sr. Technical Architect,
Polaris software Lab
<Jarno.Elovirta@
nokia.com> To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
cc: (bcc:
omprakash.v/Polaris)
03/21/2006 02:16 Subject: RE: [xsl] Problem
getting position of node
PM
Please respond
to xsl-list
Hi,
Iam attempting to append the position of the current
node to the value of each of the node's attributes but Iam
having problems in achieving this.
Iam getting the following error:
Error at xsl:value-of on line 27 of file:/D:/xamp.xsl:
Error in expression concat(., parent::node()/position()):
Unexpected token [<function>] in path expression
The line causing the problem is
<xsl:attribute name="{name(.)}">
<xsl:value-of select="concat(., parent::node()/position())"/>
parent::node()/position() is the problem, you can't use a function as a
right side operator in a path expression. Also, position() does not return
the position of a node in it's siblings, but rather the context position.
You want
<xsl:value-of select="."/>
<xsl:number count="*"/>
Cheers,
Jarno
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