Juts translate your English into XPath directly...
For my contrived example below, I would like to select
select="
all book nodes
book
whose
[
owner is "aaa"
owner='aaa'
*or*
or
which have a chapter whose owner is
"aaa",
chapter/owner='aaa']"
Putting that together:
select="book[owner is "aaa" or chapter/owner='aaa']
ALternatively you could write
select="book[owner is "aaa"] | book[chapter/owner='aaa']
The "|" operator here forms the union of two sets.
In both cases the results will be in document order, as required.
Michael Kay
http://www.saxonica.com/
and
I would like the books to be retrieved in the same general
order as the
xml document, i.e., the query for the example below would
process books
with id's 1, 3, 4 (in that order), not 1, 4, 3.
I can do the XPATH for *either* of the two cases, but don't
know how to
combine the two for an OR search in my xsl:apply-templates
select statement.
<xsl:a-t select="book[owner='aaa'] or book/chapter[owner='aaa']"/>
is kind of what I want, but Xalan is complaining that my select
attribute is just returning a boolean, so my syntax is
apparently wrong.
Any help would be much appreciated.
Thanks,
Glen
<book id="1">
<owner>aaa</owner>
<chapter>
<owner>bbb</owner>
</chapter>
<chapter>
<owner>ccc</owner>
</chapter>
</book>
<book id="2">
<owner>bbb</owner>
<chapter>
<owner>bbb</owner>
</chapter>
<chapter>
<owner>ccc</owner>
</chapter>
</book>
<book id="3">
<owner>ccc</owner>
<chapter>
<owner>aaa</owner>
</chapter>
<chapter>
<owner>ccc</owner>
</chapter>
</book>
<book id="4">
<owner>aaa</owner>
<chapter>
<owner>bbb</owner>
</chapter>
<chapter>
<owner>ccc</owner>
</chapter>
</book>
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