You haven't shown your source document, but my guess is that your font
elements are in a namespace.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Ian Eure [mailto:ieure(_at_)enotes(_dot_)com]
Sent: 19 April 2006 01:08
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Aargh - wrong template applied
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I'm sure this is something simple I'm overlooking, but I just
can't make this work.
I have this stylesheet:
<xsl:stylesheet version='1.0'
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:gale="http://www.gale.com/eBook";
xmlns:php="http://php.net/xsl";
exclude-result-prefixes="gale php">
<xsl:output method="xml"
version="1.0"
indent="yes"
encoding="utf-8"
omit-xml-declaration="yes"/>
<xsl:template match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
</xsl:template>
<xsl:template match="font">
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
I want to pass through the document as-is in most cases, but
make certain changes elsewhere. I have a generic pass-through
rule, and a more specific rule to strip out <font> elements,
but retain their children. However, the latter template is
never called, and I can't figure out why.
I'm using XSLTProc. Turning on it's verbose mode gives me
some relevant information:
added pattern : '@*' priority -0.500000
added pattern : 'node()' priority -0.500000 added pattern :
'font' priority 0.000000
Looks good, but then:
xsltProcessOneNode: applying template '@*|node()' for font
Why isn't the latter template ever applied, and how do I get
the behavior I want?
- --
Ian Eure
Developer,
eNotes.com LLC
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