Re: [xsl] Stylesheet to output XML Tags (node names)

I changed the stylesheet to output also attributes, and changed a few things:

<?xml version='1.0' encoding='ISO-8859-1'?>
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version="1.0">
        <xsl:key name="nodenames" match="*" use="name()" />
        <xsl:template match="/">
                <nodes>
                        <xsl:apply-templates select="*[count(. | 
key('nodenames', name())[1]) = 1]"/>
                </nodes>
        </xsl:template>
        <xsl:template match="*">
                <node>
                        <xsl:attribute name="name">
                                <xsl:value-of select="name()" />
                        </xsl:attribute>
                        <xsl:apply-templates select="@*"/>
                </node>
                <xsl:apply-templates select="*[count(. | key('nodenames', 
name())[1]) = 1]"/>
        </xsl:template>
        <xsl:template match="@*">
                <attr>
                        <xsl:attribute name="name">
                                <xsl:value-of select="name()" />
                        </xsl:attribute>
                </attr>
        </xsl:template>
</xsl:transform>

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