See http://www.dpawson.co.uk/xsl/sect2/N2018.html#d3114e487
In your case step 2 is to apply the translate() function.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Markus Gamperl [mailto:markus(_dot_)gamperl(_at_)gmx(_dot_)at]
Sent: 27 April 2006 15:44
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] sum up float values problem
Dear experts!
XSL 1.0:
I have got the following XML:
<POSITION>
<LSUM>14,68</LSUM>
<LSUM>321</LSUM>
<LSUM>13</LSUM>
<LSUM>100,6</LSUM>
...
</POSITION>
I want to sum up all my LSUM elements. When I do a
sum(//LSUM) I only get a number value, not a float value...
This would work if the float values are separated with a '.'
not a ',' (eg. 14.68). But I get the values separated with a ','...
So I had following idea:
sum(translate(//LSUM,',','.'))
But the translate function only returns the first node
(14.68) of the nodeset...
Do you have an idea how to solve this issue simply?
Thanks
Markus
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