Re: [xsl] Sort an xml file by the using the ordering/sorting information

Please try this

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:output method="xml" indent="yes" />

<xsl:variable name="doc" select="/" />
<xsl:variable name="sortorder" select="document('SortingOrder.xml')" />

<xsl:template match="/myRoot">
<myRoot>
  <xsl:for-each select="$sortorder/mySortingOrder/myElement">
    <xsl:copy-of select="$doc/myRoot/myElement[(_at_)key = current()/@key]" />
  </xsl:for-each>
</myRoot>
</xsl:template>

</xsl:stylesheet>

Regards,
Mukul

On 5/11/06, Jagsmiles <jagsmiles(_at_)gmail(_dot_)com> wrote:
> I want to sort the elements of an xml file, The criteria of ordering is
> actually specified in another xml file.
>
> Can i use xsl to sort one xml file by the using the ordering data from
> another xml file?:
>
> I give a small e.g.
>
> The Original xml file: main.xml
>
> <myRoot>
>        <myElement key=3D"Tokyo" country=3D"JAP">I am Tokyo</myElement>
>        <myElement key=3D"NewYork" country=3D"US">I am NewYork</myElement>
>        <myElement key=3D"Sydney" country=3D"AUS">I am Sydney</myElement>
>        <myElement key=3D"London" country=3D"UK">I am London</myElement>
> </myRoot>
>
> The Sorting Criteria xml file: SortingOrder.xml:
> <mySortingOrder>
>        <myElement key=3D"NewYork" />
>        <myElement key=3D"London" />
>        <myElement key=3D"Tokyo" />
>        <myElement key=3D"Sydney" />
> </mySortingOrder>
>
>
> After sorting the final xml data i should get is:
> <myRoot>
>        <myElement key=3D"NewYork" country=3D"US">I am NewYork</myElement>
>        <myElement key=3D"London" country=3D"UK">I am London</myElement>
>        <myElement key=3D"Tokyo" country=3D"JAP">I am Tokyo</myElement>
>        <myElement key=3D"Sydney" country=3D"AUS">I am Sydney</myElement>
> </myRoot>
>
> in the final xml, the myElement elements are sorted according to the sortin=
> g
> order specified in SortingOrder.xml.
>
> Can i achieve this using xsl?
> Normally for the xsl:sort the sorting information should be present in the
> element itself.
>
> Thanks in advance.
> Jagdishwar.
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