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RE: [xsl] Sorting an xml

2006-05-23 01:29:38
In XSLT 2.0, with shopinglist as the context item:

<xsl:for-each-group select="item" group-by="place">
  <xsl:value-of select="current-grouping-key()"/>:
  <xsl:for-each select="current-group()">
    <xsl:value-of select="count, unit, place"/>
    <xsl:text>&#xa;</xsl:text>
  </xsl:for-each>
</xsl:for-each-group>

(You said you wanted the output sorted, but your specimen output was grouped
without sorting).

Michael Kay
http://www.saxonica.com/ 

-----Original Message-----
From: Jimmy Åhs [mailto:jimmyahs(_at_)gmail(_dot_)com] 
Sent: 22 May 2006 15:48
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Sorting an xml

Hi, I'm making an application that makes a shopinglist, my 
XML might looks like this:

--------------------------------------------------------------
<shopinglist>
    <item>
        <name>Lax</name>
        <count>8</count>
        <unit>st</unit>
        <place>Kyl och frys</place>
    </item>
    <item>
        <name>Chalottenlök</name>
        <count>4</count>
        <unit>st</unit>
        <place>Frukt och grönt</place>
    </item>
    <item>
        <name>Matlagningsvin</name>
        <count>0,66</count>
        <unit>l</unit>
        <place>Övrigt</place>
    </item>
    <item>
        <name>Grädde</name>
        <count>1,2</count>
        <unit>l</unit>
        <place>Kyl och frys</place>
    </item>
</shopinglist>
----------------------------------------------------------

The printout for this should be sorted by <place> like this:
Kyl och frys:
Lax 8 st
Grädde 1,2 l

Frukt och grönt:
Chalottenlök 4 st

Övrigt:
Matlagningsvin 0,66  l



How do I do this as easy as possible?
Thnx in advance!
Jimmy

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