Re: [xsl] identify lowest value within a range of elements

I wrote: 

   something like

   <xsl:template match="price">
   <xsl:param name="range" select="../price"/>
   <xsl:param name="rangename" select="'default'"/>
   <xsl:copy>
   <xsl:if test="empty($range[number(.) &lt; number(current())])">
   <xsl:attribute name="lowest" select="$rangename"/>
   </xsl:if>
   <xsl:copy-of select="node()"/>
   </xsl:copy>
   </xsl:template>

   and

   <xsl:apply-templates select="price">
     <xsl:with-param name="rangename" select="'range1'"/>
     <xsl:with-param name="range" select="price[position[&lt; 5]"/>
   </xsl:apply-templates>


That redoes the search for the lowest value each cell which isn't very
sensible, better would be


   something like

   <xsl:template match="price">
   <xsl:param name="lowest" select="0"/>
   <xsl:param name="rangename" select="'default'"/>
   <xsl:copy>
   <xsl:if test="[$lowest= number(current())])">
   <xsl:attribute name="lowest" select="$rangename"/>
   </xsl:if>
   <xsl:copy-of select="node()"/>
   </xsl:copy>
   </xsl:template>

   and


   <xsl:apply-templates select="price">
     <xsl:with-param name="rangename" select="'range1'"/>
     <xsl:with-param name="lowest" select="min(price[position()&lt; 
5]/number(.))"/>
   </xsl:apply-templates>


David

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