xsl-list
[Top] [All Lists]

Re: [xsl] xsl:template rules seems to be ignored

2006-05-31 05:34:33
andrew welch wrote:
On 5/31/06, Stefano Lampis 
<slampis(_at_)studenti(_dot_)math(_dot_)unipd(_dot_)it> wrote:
I am quite new to XSL and I am trying to write a stylesheet to process a
log file generated with Apache Logging framework.

The XML file is like this

=== begin log.xml ===
<?xml version="1.0" ?>
<!DOCTYPE log4j:eventSet SYSTEM "log4j.dtd" [
        <!ENTITY data SYSTEM "server.xml">
        ]


<log4j:eventSet version="1.2"
xmlns:log4j="http://jakarta.apache.org/log4j/";>
        &data;
</log4j:eventSet
=== end log.xml ===

and my stylesheet is like this

=== begin log.xsl ===
<?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
<xsl:stylesheet version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
        xmlns:log4j="http://jakarta.apache.org/log4j";>

<xsl:output method="html" />

<xsl:template match="log4j:eventSet">
        <!-- Do something here -->
</xsl:template>
</xsl:stylesheet>
=== end log.xsl ===

But my template rules are ignored.
Why?

You have a trailing slash on the log4j namespace in your XML

:)

Huge thanks, I was really going crazy

-- 
Stefano Lampis

--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--

<Prev in Thread] Current Thread [Next in Thread>