Indeed, it is easier to understand and hopefully more efficient.
I changed my stylesheet to:
<xsl:for-each-group select="item" group-by="@racknum">
<p>Group racknum: <xsl:value-of
select="current-grouping-key()"/> Group max: <xsl:value-of
select="max(current-group()/@pocketnum)"/>
</p>
</xsl:for-each-group>
And now I get results:
<p>Group racknum: 1 Group max: 13</p>
<p>Group racknum: 2 Group max: 6</p>
Thank you!
-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk]
Sent: Thursday, June 08, 2006 9:38 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] "not a node item" inside distinct-values
Others have pointed to teh immediate cause of teh error message, but if
you find yourself doing this:
<xsl:for-each select="distinct-values(//item/@racknum)">
<xsl:variable name="rack-num" select="."/>
<xsl:variable name="pocket-num" select="//item[./@racknum =
$rack-num and position() = last()]"/>
9 times out of 10 its easier (and probably more efficient) to do
<xsl:for-each-group select="//item" group-by="@racknum">
(also probably //item should just be item)
David
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