Your stylesheet needs to include within it an instruction such as
<xsl:apply-templates select="document(@url)"/>
to dereference the links and recursively process the referenced document.
I don't know what this is supposed to be:
<?xml versionfiltered="1.0" encoding="UTF-8"?>
but it isn't XML.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Laky Tang [mailto:tulaky(_at_)yahoo(_dot_)com]
Sent: 20 June 2006 03:46
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Recursively merge (aggregate) and traverse DOM
trees (XML files)?
I am trying to recursively merge a tree of XML files and then
apply some templates to it. I googled and also searched this
mailing list but did not find any help. I hope this is
possible using XSLT. Can somebody please point me in the
right direction?
Here is a sample of the input files and desired output. I
tried a sample.xsl (see below)which only goes thru the root
file, but need help in making it recursively go thru all the
linked files as well.
Thanks in advance,
Laky, Tang
-----------------
sample1.xml :
<?xml versionfiltered="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="sample.xsl"?> <a> <b p
="key1" q="2"> xxx </b> <b url = "sample2.xml"></b> <b p
="key10" q ="27">yyyy</b> </a>
sample2.xml :
<?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
="key4" q="22"> xxx2 </b> <b url = "sample3.xml"></b> <b p
="key7" q ="37">yyyy2</b> <b url = "sample4.xml"></b> </a>
sample3.xml :
<?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
="key5" q="23"> xxx3 </b> <b p ="key6" q ="26">yyyy3</b> </a>
sample4.xml :
<?xml versionfiltered="1.0" encoding="UTF-8"?> <a> <b p
="key8" q="24"> xxx4 </b> <b p ="key9" q ="25">yyyy4</b> </a>
sample.xsl :
<?xml versionfiltered="1.0" encoding="UTF-8"?>
<xsl:stylesheet versionfiltered="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:fn="http://www.w3.org/2005/02/xpath-functions"
xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes"
xmlns:xlink="http://www.w3.org/1999/xlink">
<xsl:template match="/">
<html>
<head>
<title>Sample</title>
</head>
<h1>
<center>
</center>
</h1>
<p/>
<xsl:for-each xml:space="default" select="param">
<xsl:value-of select="."/> </xsl:for-each> <table border="2"
bgcolor="yellow"> <tr> <th>P</th> <th>Q</th> <th>text</th>
</tr> <xsl:for-each select="//b"> <tr> <td> <xsl:value-of
select="@p"/> </td> <td> <xsl:value-of select="@q"/> </td>
<td> <xsl:value-of select="."/> </td> </tr> </xsl:for-each>
</table> </html> </xsl:template> </xsl:stylesheet>
Desired output (preferably as a html table):
P Q text
key1 2 xxx
key4 22 Xxx2
key5 23 xxx3
key6 26 yyy3
Key7 37 yyy2
key8 24 xxx4
key9 25 yyy4
key10 27 yyyy
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