Hi Bernie,
Please try this stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" />
<xsl:template match="/root">
<html>
<head>
<title/>
</head>
<body>
<xsl:call-template name="GenerateBreadcrumbs">
<xsl:with-param name="x" select="breadCrumbs" />
<xsl:with-param name="y" select="breadCrumbsUrls" />
</xsl:call-template>
</body>
</html>
</xsl:template>
<xsl:template name="GenerateBreadcrumbs">
<xsl:param name="x" />
<xsl:param name="y" />
<xsl:choose>
<xsl:when test="$y != ''">
<xsl:choose>
<xsl:when test="contains($y,',')">
<a href="{substring-before($y,
',')}"><xsl:value-of select="substring-before($x, ',')"
/></a><xsl:text> </xsl:text> >
</xsl:when>
<xsl:otherwise>
<a href="{$y}"><xsl:value-of
select="substring-before($x, ',')" /></a><xsl:text> </xsl:text> >
</xsl:otherwise>
</xsl:choose>
<xsl:call-template name="GenerateBreadcrumbs">
<xsl:with-param name="x"
select="substring-after($x, ',')" />
<xsl:with-param name="y" select="substring-after($y, ',')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$x" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
On 6/21/06, Bernie <berniecc(_at_)gmail(_dot_)com> wrote:
With the next XML:
<?xml version="1.0" encoding="utf-8"?>
<root>
<breadCrumbs>Home page,Section 1,Chapter2</breadCrumbs>
<breadCrumbsUrls>linkToHome.html,linkToSec1.html</breadCrumbsUrls>
</root>
can you tell me the XSL code to produce the next HTML?
<a href="linkToHome.html">Home page</a> > <a
href="linkToSec1.html">Section 1</a> > Chapter 2
Thank you very much in advance.
Bernie
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