Here is a Saxon (8.7.3J) specific solution:
file1.xml
------------
<a>
<b>
<node>1</node>
</b>
<c>
<d>
<node>2</node>
</d>
</c>
</a>
file2.xml
------------
<a>
<b val="x">
<node width="10"/>
</b>
<c>
<d val="z">
<node height="15"/>
</d>
</c>
</a>
merge.xsl
--------------
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:saxon="http://saxon.sf.net/";>
<xsl:output method="xml" indent="yes" />
<xsl:variable name="file2" select="document('file2.xml')" />
<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="$file2//*[saxon:path() =
current()/saxon:path()]/@*" />
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
java net.sf.saxon.Transform file1.xml merge.xsl
Warning: Running an XSLT 1.0 stylesheet with an XSLT 2.0 processor
<?xml version="1.0" encoding="UTF-8"?>
<a>
<b val="x">
<node width="10">1</node>
</b>
<c>
<d val="z">
<node height="15">2</node>
</d>
</c>
</a>
Regards,
Mukul
On 6/22/06, Minervini, Chris
<christopher(_dot_)minervini(_at_)lehman(_dot_)com> wrote:
O.K. here's my question. It seems like it should be simple but I can't
figure it out.
I have two XML files. One with data in the node values, and one with
data in attributes. They have the same exact structure.
<a>
<b>
<node>1</node>
</b>
<c>
<d>
<node>2</node>
</d>
</c>
</a>
... and ...
<a>
<b val="x">
<node width="10"/>
</b>
<c>
<d val="z">
<node height="15"/>
</d>
</c>
</a>
As you can see the word "node" node appears at /a/b/node and a/c/d/node
but has two distinct values and attributes.
Is there a way to transform the first one with XSLT to produce the
following results:
<a>
<b val="x">
<node width="10">1</node>
</b>
<c>
<d val="z">
<node height="15">2</node>
</d>
</c>
</a>
...essentially combining the node values of one file with the attributes
in the other.
I've really been struggling with this. I was able to do it with
recursion, but I'm looking for a way to do it without using recursive
procedures. I don't think it's possible. Is it?
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