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[xsl] returning nodes (not a string) using variable-choose.

2006-06-23 12:05:56
The below somewhat elaborate lines assign a value to $typeInfo,
however they don't return results as a nodelist, just a big string.
------

<xsl:variable name="typeInfo">
        <xsl:choose>
                <xsl:when test="$type='Other'">
                        <xsl:value-of select="$desc" />
                </xsl:when>
                <xsl:otherwise>
                        <xsl:variable name="table">
                                <xsl:choose>
                                        <xsl:when test="$type='Organizational 
Contact'">
                                                <xsl:text>CA_Orgs</xsl:text>
                                        </xsl:when>
                                        <xsl:when test="$type='Meeting or 
Training'">
                                                <xsl:text>CA_Meetings</xsl:text>
                                        </xsl:when>
                                        <xsl:when test="$type='Travel'">
                                                <xsl:text>CA_Travel</xsl:text>
                                        </xsl:when>
                                </xsl:choose>
                        </xsl:variable>
                        <xsl:value-of
select="document(concat(concat(concat('http://server.org/getXML.asp?key=id&amp;val=',$desc),'&amp;table='),$table))"
/>
                </xsl:otherwise>
        </xsl:choose>
</xsl:variable>
<xsl:value-of select="$typeInfo" />
-----------------

Anyway to do this with XSLT 1.0 or am I pushing it?

--Steve

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