RE: [xsl] values in sequence after tokenize

position() gives you the position of a substring within the sequence of
matching and non-matching substrings. To get the position within the
sequence of matching substrings only, I think you will need a second pass.

Michael Kay
http://www.saxonica.com/

-----Original Message-----
From: Florent Georges [mailto:darkman_spam(_at_)yahoo(_dot_)fr] 
Sent: 11 July 2006 15:53
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] values in sequence after tokenize

andrew welch wrote:

  Hi

Using xsl:analyze-string, how would I add a count to the matching
items:

<xsl:analyze-string select="$string" regex=".{{1,6}}\^">
  <xsl:matching-substring>
    <line count="{ ?? }"><xsl:value-of select="."/></line>
  </xsl:matching-substring>
  <xsl:non-matching-substring>
    <non><xsl:value-of select="."/></non>
  </xsl:non-matching-substring>
</xsl:analyze-string>

...so that the output would be:

<line count="1">....
<line count="2">....

Is this possible or does it require two passes?


  I'm not sure, but if I understood well, you need simply position():

    ~/xslt/tests> cat analyse-string.xsl
    <xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                   version="2.0">

      <xsl:output indent="yes" omit-xml-declaration="yes"/>

      <xsl:param name="input" select="'aa^aaa^aaa^^aa'"/>

      <xsl:template name="main">
        <xsl:analyze-string select="$input" regex=".{{1,6}}\^">
          <xsl:matching-substring>
            <line count="{ position() }">
              <xsl:value-of select="."/>
            </line>
          </xsl:matching-substring>
          <xsl:non-matching-substring>
            <non>
              <xsl:value-of select="."/>
            </non>
          </xsl:non-matching-substring>
        </xsl:analyze-string>
      </xsl:template>

    </xsl:transform>

    ~/xslt/tests> saxon -it main analyse-string.xsl
    <line count="1">aa^</line>
    <line count="2">aaa^</line>
    <line count="3">aaa^</line>
    <non>^aa</non>

  Regards,

--drkm

























      

      
              
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