You could produce the error only once by writing
count(preceding-sibling::key[. = current()] = 1)
or if you prefer:
following-sibling::key[. = current()] and not(preceding-sibling::key[. =
current()])
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Todd Ditchendorf [mailto:itod(_at_)apple(_dot_)com]
Sent: 19 July 2006 22:52
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] More XPath 1.0 Expression help
Thanks Mike and Spencer, that definitely got me going in the
right direction!
However, I don't think I have XSLT grouping available to me
in this case... let me explain.
This XPath is to be used in a Schematron <sch:asstert> test
attribute. I am using the XSLT ref impl of Schematron 1.5
running against libxslt witch is limited to XSLT 1.0 and
XPath 1.0. I don't think i can access exslt from the
schematron schema ,so exslt is out.
Also, I'm assuming that I cannot access XSLT grouping
mechanisms from within the schematron schema, so that,
unfortunately, is out too. :
( Please correct me if I'm wrong there.
So here's what i've got so far:
<sch:pattern name="Report Duplicate Keys">
<sch:rule context="/plist/dict/key">
<sch:assert
test="count(../key[.=current()]) = 1">
Duplicate
'<sch:value-of select="."/>' key exists
<sch:value-of
select="count(../key[.=current()])"/> times.
Keys should be
unique.</sch:assert>
</sch:rule>
</sch:pattern>
So I have access to the XSLT current() func but no XSLT
grouping features AFAIK. This rule gets the job of detecting
duplicate keys done... unfortunately it also raises n errors
for n duplicate keys rather than just one error for n
duplicate keys. That's certainly not a show-stopper... but it
would be nice to fix.
Any ideas?
The O(n^2) complexity doesn't bother me in this instance as
perf is not a prime concern here and the data set is very
small anyway.
Here's what the actual input looks like... it's an Apple plist:
<plist>
<dict>
<key>Key1</key>
<value/>
<key>Key2</key>
<value/>
<key>Key3</key>
<value/>
<key>Key1</key>
<value/>
</dict>
</plist>
Todd
On Jul 19, 2006, at 2:22 PM, Michael Kay wrote:
Take a look at http://www.jenitennison.com/xslt/grouping
Most of the techniques for grouping are at the XSLT level,
but you can use the basic
key[not(. = preceding-sibling::key)]
if you don't mind O(n^2) complexity.
This detects the distinct values: leave out the not() and you
have an expression that detects the duplicates.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Todd Ditchendorf [mailto:itod(_at_)apple(_dot_)com]
Sent: 19 July 2006 22:18
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] More XPath 1.0 Expression help
I need some help constructing an XPath to detect nodes
containing duplicate string-values. I am currently restricted
to XPath 1.0 syntax , so no access to distinct-values() or
exslt unfortunately.
I have a document like this:
<dict>
<key>Key1</key>
<value/>
<key>Key2</key>
<value/>
<key>Key3</key>
<value/>
<key>Key1</key>
<value/>
</dict>
How do I create an XPath 1.0 expression to detect the <key>
elements with duplicate string-values?
Thanks!
Todd Ditchendorf
Software Engineer
itod(_at_)apple(_dot_)com
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