You haven't shown your source code so it's hard to see where you're going
wrong.
If you do
<xsl:apply-templates select="section, ref, ack, app"/>
then the sections will be processed in that order, and position() used
within the relevant templates will give you consecutive numbering. Also
count(section|ref|ack|app) will give you the right total.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Karl [mailto:call14(_at_)yahoo(_dot_)com]
Sent: 20 July 2006 10:50
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Is there any multiple if exression (not
xsl:if) available in xpath/xslt2 ?
I have an xml having some 'n' number of <section>'s + 3
OPTIONAL elemts <ref>, <ack> and <app>, which must appear in
that order.
Though my actual reqmt is to generate html pages in that
names with links from every page, what in essence i would
prefer to get is
1. section 1
2. section 2
...
n. section n
n+1 ref
n+2 ack
n+3 app
The problem is if ref is not present, it will be n. section n
n+1 ack
n+2 app
or if ack not there
n+1 ref
n+2 app
and the combination can be anything as those 3 elemts are
optional. I can have many <xsl:if>s to find and get what i
want. But is there a elegant solution or expression (can be
even xslt 2/xpath 2) that will reduce multiple if stmts?
Also, i need to count Total num of pages. Is there any expr
like Total pages = <xsl:value of select"count(//section) +
if(ref) add 1 + if (ack) add 1 + if(app) add 1"/>
Thanks
karl
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