Hi Peter
Ahhh.... It looks great!!! So, it is possible to have numerous
grouping combinations in version 1.0.
Thank you very much!!!
Steve
-----------------------------
Hi All
Is it possible to have a group within a group. I did look at
http://www.biglist.com/lists/xsl-list/archives/200101/msg00070.html
but I either get a date with data from both dates or the same date for
each data set.
Thank You
Steve
Desire Sample Output
--------------------
07-13-2006
USA
Group Name id
AAA Adel 12345
AAA Barry 12346
AAA Carl 12347
BBB Dave 12345
BBB Ethel 12346
BBB Fred 12347
EUR
Group Name id
CCC George 24567
CCC Harold 23458
CCC Jennifer 23459
07-14-2006
USA
Group Name id
BBB Dave 12345
BBB Ethel 12346
BBB Fred 12347
EUR
Group Name id
CCC George 24567
CCC Harold 23458
CCC Jennifer 23459
=====================================
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="html" indent="yes" />
<xsl:key name="by-date" match="entry" use="date" />
<xsl:key name="by-country" match="entry" use="country" />
<xsl:template match="/report">
<html>
<head>
<title/>
</head>
<body>
<table border="1">
<xsl:variable name="break_by_date"
select="//entry[key('by-date', date)]"/>
<xsl:variable name="break_by_country" select="key('by-country',
currency)"/>
<xsl:for-each select="$break_by_date[generate-id() =
generate-id(key('by-country', country)[1])]">
<tr>
<td><xsl:value-of select="date"/></td>
</tr>
<tr>
<td><xsl:value-of select="country" /></td>
</tr>
<tr>
<td>Group</td>
<td>Name</td>
<td>id</td>
</tr>
<xsl:for-each select="key('by-country', country)">
<tr>
<td><xsl:value-of select="../@type" /></td>
<td><xsl:value-of select="name" /></td>
<td><xsl:value-of select="id" /></td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Sample XML file
<report>
<table>
<date>07-13-2006
<group type="AAA">111111
<entry>
<date>07-13-2006</date>
<name>Adel</name>
<country>USA</country>
<id>12345</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Barry</name>
<country>USA</country>
<id>12346</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Carl</name>
<country>USA</country>
<id>12347</id>
</entry>
</group>
<group type="BBB">111111
<entry>
<date>07-13-2006</date>
<name>Dave</name>
<country>USA</country>
<id>12345</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Ethel</name>
<country>USA</country>
<id>12346</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Fred</name>
<country>USA</country>
<id>12347</id>
</entry>
</group>
<group type="CCC">111111
<entry>
<date>07-13-2006</date>
<name>George</name>
<country>EUR</country>
<id>24567</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Harold</name>
<country>EUR</country>
<id>23458</id>
</entry>
<entry>
<date>07-13-2006</date>
<name>Jennifer</name>
<country>EUR</country>
<id>23459</id>
</entry>
</group>
</date>
<date>07-14-2006
<group type="BBB">111111
<entry>
<date>07-14-2006</date>
<name>Dave</name>
<country>USA</country>
<id>12345</id>
</entry>
<entry>
<date>07-14-2006</date>
<name>Ethel</name>
<country>USA</country>
<id>12346</id>
</entry>
<entry>
<date>07-14-2006</date>
<name>Fred</name>
<country>USA</country>
<id>12347</id>
</entry>
</group>
<group type="CCC">111111
<entry>
<date>07-14-2006</date>
<name>George</name>
<country>EUR</country>
<id>24567</id>
</entry>
<entry>
<date>07-14-2006</date>
<name>Harold</name>
<country>EUR</country>
<id>23458</id>
</entry>
<entry>
<date>07-14-2006</date>
<name>Jennifer</name>
<country>EUR</country>
<id>23459</id>
</entry>
</group>
</date>
</table>
</report>
------------------------------
Date: Fri, 21 Jul 2006 15:17:17 -0400
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
From: "Jacoby, Peter R." <PJACOBY(_at_)PARTNERS(_dot_)ORG>
Subject: RE: [xsl] Multiple Grouping & Muenchian Method
Message-ID:
<3CFEFF6C55FB5C42A6E68E9521D5C436025FA18F(_at_)PHSXMB9(_dot_)partners(_dot_)org>
Is it possible to have a group within a group.=20
Hi, Steve,
You were really close in your code. The concept that you were missing =
is to
define one xsl:key with two parameters using the concat function.
If you change your key declaration to be
<xsl:key name=3D"byDateAndCountry" match=3D"entry"
use=3D"concat(parent::group/parent::date/text(), country)" />
or more succinctly:
<xsl:key name=3D"byDateAndCountry" match=3D"entry" =
use=3D"concat(../../text(),
country)" />
You can then call one key indexed by an entry's date as well as country.
A full stylesheet is below. Please let us know if you have any other =
questions.
This all becomes a lot easier in 2.0 with xsl:for-each-group. Hopefully =
someone
will post the 2.0 solution so we can see how much simpler it is.
-Peter
<?xml version=3D"1.0" ?>
<xsl:stylesheet version=3D"1.0" =
xmlns:xsl=3D"http://www.w3.org/1999/XSL/Transform";>
<xsl:output method=3D"xml" omit-xml-declaration=3D"no" indent=3D"yes"
encoding=3D"UTF-8"/>
<xsl:key name=3D"byDateAndCountry" match=3D"entry" =
use=3D"concat(../../text(),
country)" />
<xsl:template match=3D"/">
<table border=3D"1">
<xsl:apply-templates select=3D"report/table/date"/>
</table>
</xsl:template>
<xsl:template match=3D"date">
<tr>
<td>
<xsl:value-of select=3D"normalize-space(text())" />
</td>
</tr>
=09
<xsl:for-each select=3D"group/entry[generate-id() =3D
generate-id(key('byDateAndCountry', concat(../../text(), =
country))[1])]">
<tr>
<td>
<xsl:value-of select=3D"country" />
</td>
</tr>
<tr>
<td>Group</td>
<td>Name</td>
<td>ID</td>
</tr>
<xsl:apply-templates select=3D"key('byDateAndCountry',
concat(../../text(), country))" />
</xsl:for-each>
</xsl:template>
<xsl:template match=3D"entry">
<tr>
<td>
<xsl:value-of select=3D"../@type" />
</td>
<td>
<xsl:value-of select=3D"name" />
</td>
<td>
<xsl:value-of select=3D"id" />
</td>
</tr>
</xsl:template>
</xsl:stylesheet>
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