Thanks Mukul,
The levels are only 3 yes. But how to use heirarchy
XML made by template. This is what I trying:
<?xml version="1.0" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/records">
<records>
<xsl:for-each select="record[parentkeynum = 0]">
<record>
<xsl:variable name="key1" select="keynum" />
<xsl:copy-of select="*" />
<xsl:for-each select="../record[parentkeynum =
$key1]">
<record>
<xsl:variable name="key2" select="keynum"
/>
<xsl:copy-of select="*" />
<xsl:for-each
select="../record[parentkeynum = $key2]">
<record>
<xsl:copy-of select="*" />
</record>
</xsl:for-each>
</record>
</xsl:for-each>
</record>
</xsl:for-each>
</records>
<xsl:call-template name="dve">
</xsl:call-template>
</xsl:template>
<xsl:template name="dve" match="/">
<xsl:for-each select="//records/record">
<xsl:call-template name="SubMenu">
<xsl:with-param name="strCSS">Parent
IsVisible</xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="SubMenu">
<xsl:param name="strCSS" />
<div class="{$strCSS}">
<xsl:choose>
<xsl:when test="count(record) > 0">
<!-- Element has children, it can be expanded -->
<input type="hidden" id="hidIsExpanded" value="0"
/>
<label id="lblExpand" class="Expander"
onclick="ExpanderClicked()">+ </label>
</xsl:when>
<xsl:otherwise>
<label class="Expander">  </label>
</xsl:otherwise>
</xsl:choose>
<a><xsl:value-of select="keyname" /></a>
<xsl:for-each select="record">
<xsl:call-template name="SubMenu">
<xsl:with-param
name="strCSS">NotVisible</xsl:with-param>
</xsl:call-template>
</xsl:for-each>
</div>
</xsl:template>
</xsl:stylesheet>
and than I use this ASP
<%@ Language=VBScript %>
<% option explicit %>
<HTML>
<HEAD>
<link type="text/css" rel="stylesheet"
href="alerts.css" />
</HEAD>
<BODY>
<b>Alerts</b>
<%
dim xmlMenu
dim xslMenu
'Get the source XML
set xmlMenu = server.CreateObject("Microsoft.XMLDOM")
xmlMenu.async = false
xmlMenu.load server.MapPath("probe.xml")
'Get the XSLT to transform the XML
set xslMenu = server.CreateObject("Microsoft.XMLDOM")
xslMenu.async = false
xslMenu.load server.MapPath("probe.xsl")
'Transform the source XML using XSLT
Response.Write xmlMenu.transformNode(xslMenu)
set xmlMenu = nothing
set xslMenu = nothing
%>
<script language="jscript">
function ExpanderClicked()
{
//Get the element that was clicked
var ctlExpander = event.srcElement;
var ctlSelectedEntry = ctlExpander.parentElement;
//Get all the DIV elements that are direct
descendants
var colChild = ctlSelectedEntry.children.tags("DIV");
if(colChild.length > 0)
{
var strCSS;
//Get the hidden element that indicates whether or
not entry is expanded
var ctlHidden =
ctlSelectedEntry.all("hidIsExpanded");
if(ctlHidden.value == "1")
{
//Entry was expanded and is being contracted
ctlExpander.innerHTML = "+ ";
ctlHidden.value = "0";
strCSS = "NotVisible";
}
else
{
//Entry is being expanded
ctlExpander.innerHTML = "- ";
ctlHidden.value = "1";
strCSS = "IsVisible";
}
//Show all the DIV elements that are direct children
for(var intCounter = 0; intCounter <
colChild.length; intCounter++)
{
colChild[intCounter].className = strCSS;
}
}
}
</script>
</BODY>
</HTML>
But it dont working. When I trying with other XML who
is heirarchy by default it works. So my question is
how use the heirarchy XML immediantly after template
who makes it?
--- Mukul Gandhi <gandhi(_dot_)mukul(_at_)gmail(_dot_)com> wrote:
If the levels would be limited to 3 only (or can
there be any number
of levels?), then the following stylesheet would
work:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes"/>
<xsl:template match="/records">
<records>
<xsl:for-each select="record[parentkeynum = 0]">
<record>
<xsl:variable name="key1" select="keynum" />
<xsl:copy-of select="*" />
<xsl:for-each select="../record[parentkeynum
= $key1]">
<record>
<xsl:variable name="key2"
select="keynum" />
<xsl:copy-of select="*" />
<xsl:for-each
select="../record[parentkeynum = $key2]">
<record>
<xsl:copy-of select="*" />
</record>
</xsl:for-each>
</record>
</xsl:for-each>
</record>
</xsl:for-each>
</records>
</xsl:template>
</xsl:stylesheet>
Regards,
Mukul
http://gandhimukul.tripod.com
On 7/23/06, Radoslav Kolarov <roonex(_at_)yahoo(_dot_)com>
wrote:
Mukul thanks for the answer. The problem is how to
turn tree structured information into dynamic tree
menu. I found some js scripts but I can use them
only
if XML is structured heirarchy. So I have to
transform
XML to this:
<?xml version="1.0" ?>
- <records>
- <record>
<keynum>-100000</keynum>
<keyname>FINANCIAL ALERTS (5)</keyname>
<parentkeynum>0</parentkeynum>
<rowcnt>5</rowcnt>
<balance>0</balance>
- <record>
<keynum>-1</keynum>
<keyname>2 CLIENTS HAVE A NEGATIVE
BALANCE</keyname>
<parentkeynum>-100000</parentkeynum>
<rowcnt>2</rowcnt>
<balance>0</balance>
- <record>
<keynum>35</keynum>
<keyname>35 MR. MICHAEL NOLAN</keyname>
<parentkeynum>-1</parentkeynum>
<rowcnt>1</rowcnt>
<balance>-275</balance>
</record>
- <record>
<keynum>142</keynum>
<keyname>142 MR. JOHN CALINSKI</keyname>
<parentkeynum>-1</parentkeynum>
<rowcnt>1</rowcnt>
<balance>-11</balance>
</record>
</record>
</record>
</records>
Where the elements witn parentkeynum=0 to be
roots,
and elements with parentkeynum=root keynum to be
their
childrens nodes, and same thing for third level.
So
the question now is how to transform flat XML to
heirarchy XML file like this...
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