The problem is I have various <section> elemts, with some having
<subsection>'s. So, I need to create a sequence order/pagebreak at
<subsection>'s SKIPING 'section', if <subsection>'s are available
under section. Otherwise pagebreak at <section>.
e.g.
<section/> will become 1.Section title in list + creat pg 1
<section/> ..
<section/> will become list num 3.Section title & pg 3
<section> ** [No pagebreaks/pagenums SINCE IT HAS <subsection> Pg 4
moved to subsection
<subsection/> So, this become 4. Subsection title (pg 4)
<subsection/>
<subsection/> will become 6. Subsection title (pg 6)
<section>
<section/> will become 7.Section title (pg 7)
<section>
<subsection/> will become 8. Subsection title (pg 8)
<section>
and so on...
so, looks like if i write something like
<for-each - //section[with no subsection] | //section/subsection..>
and then using position(), will i get the correct order>.
1) Whether the above code is correct or not, pls can forward me the
syntax code equivalent to <for-each - //section[with no subsection] |
//section/subsection..>
2) If the above is not correct, pls can you suggest some effective
solution?
Thanks in adv.
karl
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