<xsl:param name="linestyle" select="Solid" />
that selects the <Solid> child element of the current node. I suspect
taht you want a default of
<xsl:param name="linestyle" select="'Solid'" />
<xsl:variable name="UnusedParamsA" select="0,0,1,300," />
that's an XPath1 syntax error, your stylesheet shouldn't compile, I
suspect that you again want
<xsl:variable name="UnusedParamsA" select="'0,0,1,300,'" />
Is there a way to pass the parameter if the tested attribute exists and
not pass anything, not even an empty string, if it does not?
only by putting the call-template inside each branch of an xsl:choose,
and passing the param in one case and not in the other.
I would however write
<xsl:with-param name="linestyle" >
<xsl:choose>
<!-- if a linestyle is specified...-->
<xsl:when test="[(_at_)name =$MatchedEntityName]/@linestyle">
^^^ again that is a syntax error
you can't start an xpath with [
<!-- ... pass it's value, otherwise... -->
<xsl:value-of select="$MatchedEntityName]/@linestyle "
/>
</xsl:when>
<xsl:otherwise>
<!-- pass nothing. -->
<xsl:value-of select="''"/>
</xsl:otherwise>
</xsl:choose>
</xsl:with-param>
as
<xsl:with-param name="linestyle"
select=*[(_at_)name=$MatchedEntityName]/@linestyle"/>
then you are always passing $linestyle either with the correct value or
with an empty node set, so your template can go (I'm assuming you want a
* at the start of taht xpath)
<xsl:choose>
<xsl:when test="$linestyle"><xsl:value-of select="$linestyle"/></xsl:when>
<xsl:otherwise>Solid</xsl:otherwsie>
David
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