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RE: [xsl] Modifying select attribute values in XHTML

2006-08-17 12:19:58
Hi Mukul,

I think this may be identical to what I had earlier when I began working
on this. I know I just tried it again at got the same results: it
outputs the value of the attributes as text node children of the
elements, and fails to go deeper than one level down the descendant
axis. 

If I could get it to follow the tree down the descendant axis, the
formatting of the output should be fairly straight forward.

-- Brook

-----Original Message-----
From: Mukul Gandhi [mailto:gandhi(_dot_)mukul(_at_)gmail(_dot_)com] 
Sent: Thursday, August 17, 2006 11:00 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Modifying select attribute values in XHTML

Hi Brook,
   I think we can write something like this (this is just a modified
identity stylesheet):

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

 <xsl:output method="xml" indent="yes" />

 <xsl:variable name="nonSecureHost" select="'http//www.example.com'" />
<xsl:variable name="imagePath" select="'http//images.example.com'" />

 <xsl:template match="node() | @*">
   <xsl:copy>
     <xsl:apply-templates select="node() | @*" />
   </xsl:copy>
 </xsl:template>

 <xsl:template match="@href">
  <xsl:attribute name="href">
  <xsl:value-of select="$nonSecureHost"/>
  <xsl:value-of select="."/>
  </xsl:attribute>
 </xsl:template>

 <xsl:template match="@src">
   <xsl:attribute name="src">
    <xsl:value-of select="$imagePath"/>
    <xsl:value-of select="."/>
   </xsl:attribute>
 </xsl:template>

</xsl:stylesheet>


On 8/17/06, Brook Ellingwood <belling(_at_)rei(_dot_)com> wrote:
Hi,

I have XML that contains small sections of XHTML, within an element 
named 'xhtml.' I need to take the XHTML and prepend the value of 
variables into the attribute values for any 'src' or 'href'
attributes.
Other than this, the XHTML needs to be passed transparently. I quickly

came up with a series of templates that works properly two levels down

from the 'xhtml' element, but I need this to work no matter how deeply

nested the decendent nodes are. I'd like to avoid recursion if at all 
possible, and it seems to me that I should be able to do this with a 
simple template match, but I keep not quite getting it.

Sample XML:
<xhtml>
<div style="width:570px;text-align:center;">
 <img src="/path/to/img.jpg" width="570" height="100" border="0"
alt="Alt text"/>
 <p style="margin:10px 0 0 0;" class="class">Display copy<br/>  <a 
href="/link">Linked text</a><br/>  <form>
  <select style="margin-top:0px;" size="1" name="selectMenu">
   <option value="#" selected="selected">Choose an option</option>
   <option value="one.html">One</option>
   <option value="two.html">Two</option>  </form>  </p> </div> <br/> 
</xhtml>

Desired sample output:

<div style="width:570px;text-align:center;">
 <img src="http//images.example.com/path/to/img.jpg" width="570"
height="100" border="0" alt="Alt text"/>  <p style="margin:10px 0 0 
0;" class="class">Display copy<br/>  <a 
href="http//www.example.com/link">Linked text</a><br/>  <form>
  <select style="margin-top:0px;" size="1" name="selectMenu">
   <option value="#" selected="selected">Choose an option</option>
   <option value="one.html">One</option>
   <option value="two.html">Two</option>  </form>  </p> </div> <br/>

XSL that I've been working with:

<xsl:template match="xhtml/*">
 <xsl:copy>
 <xsl:copy-of select="@*[not(name()='src' or name()='href')]"/>
   <xsl:apply-templates select="*"/>
 </xsl:copy>
</xsl:template>

<xsl:template match="a">
 <xsl:copy>
 <xsl:copy-of select="@*[not(name()='src' or name()='href')]"/>  
<xsl:apply-templates select="@href"/>  </xsl:copy> </xsl:template>

<xsl:template match="@href">
 <xsl:attribute name="href">
 <xsl:value-of select="$nonSecureHost"/>  <xsl:value-of select="."/>  
</xsl:attribute> </xsl:template>

<xsl:template match="img">
 <xsl:copy>
 <xsl:copy-of select="@*[not(name()='src' or name()='href')]"/>  
<xsl:apply-templates select="@src"/>  </xsl:copy> </xsl:template>

<xsl:template match="@src">
 <xsl:attribute name="src">
 <xsl:value-of select="$imagePath"/>
 <xsl:value-of select="."/>
 </xsl:attribute>
</xsl:template>

Thanks,
-- Brook

--
Regards,
Mukul Gandhi

http://gandhimukul.tripod.com

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