Yes. I see that your problem is one of imposing an explicit structure where
only an implicit structure exists.
Start with this link
"http://www.biglist.com/lists/xsl-list/archives/200012/msg00175.html";.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Sam Carleton <scarleton(_at_)miltonstreet(_dot_)com>
Sent: Tue, 22 Aug 2006 07:52:09 -0400
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] recursive template call, howto
Charles,
Thank you, that gets me very close, except...
When I transformed the xml using the style sheet you provided, I got this:
<table>
<tr><td>1</td></tr>
<tr><td>2</td></tr>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
</table>
<table>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
</table>
The problem is that the two simple groups that came after the complex
group (lines 7 and 8) need to be in their own table after the complex
group, like this:
<table>
<tr><td>1</td></tr>
<tr><td>2</td></tr>
</table>
<table>
<tr><td>3</td></tr>
<tr><td>4</td></tr>
<tr><td>5</td></tr>
<tr><td>6</td></tr>
</table>
<table>
<tr><td>7</td></tr>
<tr><td>8</td></tr>
</table>
Sam
On 8/22/06, cknell(_at_)onebox(_dot_)com <cknell(_at_)onebox(_dot_)com> wrote:
Taking the liberty of assuming a document root named "root-element" (just
substitute whatever is the case in your document), this will do what you
asked. "Look Ma! No recursion!" (Pardon an American old enough to remember
1950's TV ads.)
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="root-element">
<html>
<body>
<table>
<xsl:apply-templates select="group[not(@type)]" />
</table>
<xsl:apply-templates select="group[(_at_)type]" />
</body>
</html>
</xsl:template>
<xsl:template match="group[not(@type)]">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="group[(_at_)type]">
<table>
<xsl:apply-templates />
</table>
</xsl:template>
<xsl:template match="line">
<tr><td><xsl:value-of select="@id" /></td></tr>
</xsl:template>
</xsl:stylesheet>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Sam Carleton <scarleton(_at_)miltonstreet(_dot_)com>
Sent: Mon, 21 Aug 2006 22:13:53 -0400
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] recursive template call, howto
Here is the data:
<group>
<line id = "1"/>
</group>
<group>
<line id="2"/>
</group>
<group type="complex">
<line id="3"/>
<line id="4"/>
<line id="5"/>
<line id="6"/>
</group>
<group>
<line id="7"/>
</group>
<group>
<line id="8"/>
</group>
The idea behind the data is that there are two types of groups: simple
and complex. The simple do not have a "type" attribute (it could if it
would help things). The end result should be HTML where the first two
simple groups are in one HTML table, than there is a second table for
each of the complex groups and thing a final table for the last three
simple groups. The order of simple and complex groups is random.
My thought was when the first simple group was encountered, call a
recursive template starting at the simple group and building a nodeset
of lines until a complex group or the end was encountered. I cannot
figure out how to do that in xsl. Am I on the right path? If so, how
do I do it? If not, what is the right path?
sam
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