No, either you, or we, still don't get it.
XSLT files exist only for the purpose of transforming an XML document into
another document. That means that in order to get a meaningful answer to your
question, you need to pose in at least two parts.
Part 1
This is my XML file. (You have already given us that.)
Part B
This is what I want my output to be. (You seem to be missing out on this
concept.)
P.S. What's Java got to do with this?
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Senthilkumaravelan Krishnanatham <senthil(_at_)apple(_dot_)com>
Sent: Wed, 23 Aug 2006 10:15:01 -0700
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Java program to Generate plain XSLT for XML
To be more precise,
Say I have an XML as test.xml
like
<PERSONS>
<TEST>
<NAME>SENTHIL</NAME>
<AGE></AGE>
</TEST>
<TEST>
<NAME>SENTHIL</NAME>
<AGE></AGE>
</TEST>
<TEST>
<NAME>SENTHIL</NAME>
<AGE></AGE>
</TEST>
</PERSONS>
I except my java program to generate XSL for all the element in XML.
Elements are in Dynamic in nature.
Hope I am clear what I am looking for,
Thanks,
Senthil
On Aug 23, 2006, at 9:52 AM, cknell(_at_)onebox(_dot_)com wrote:
Someone creates an XSLT file to produce a new file by transforming
one (or more) original
XML documents.
Actually, you don't really have to change anything at all. A
perfectly legitimate (although not very useful) XSLT file,
<?xml version="1.0"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform">
<xsl:template match="/">
<xsl:copy-of select="." />
</xsl:template>
</xsl:stylesheet>
simply makes a copy of the original.
Since XSLT files are created to produce a specific output, you
first need to decide what you want the output document to look like
before you can design an XSLT file to produce it.
Perhaps you could refine your question and give more specifics.
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Senthilkumaravelan Krishnanatham <senthil(_at_)apple(_dot_)com>
Sent: Wed, 23 Aug 2006 09:29:48 -0700
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Java program to Generate plain XSLT for XML
Hi All,
I am new to this group and I found interesting about the group.
I need a startup kit kind of thing.Is there any program which would
help me to create a XSLT for any given XML file .
Please throw light light on it. That would be much help.
Thanks for your support.
Regards,
Senthil
On Aug 22, 2006, at 1:27 PM, Michael Kay wrote:
<xsl:template match="list">
<fo:list-block>
<xsl:apply-templates select="@*
That will apply-templates to the attributes of the list element,
but if
you've written any template rules that match attributes, you
haven't shown
them to us.
| *[contains(@type,
$my_version) or string-length(@type)=0] | text()"/>
That will match children of the list element that have a type
attribute
satisfying certain conditions, but in the XML you showed us, no
children of
the list element have a type attribute.
| text()"/>
That will match text node children of the list element, but in the
data you
showed us, the only text node children of the list element were
whitespace.
Michael Kay
http://www.saxonica.com/
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