[xsl] Select value by position

Hi All,

I'm trying to transform xml to rdf. And found that some elements have more 
than one values. 

And I need to select one value from several. 

For example, dc:identifier has two values. And need to choose the second 
one. 
<dc:identifier>190511</dc:identifier>
<dc:identifier>http://content.wsulibs.wsu.edu/u?/avery,0</dc:identifier>

Here is my current xslt. 
<xsl:template match="/">
<rdf:RDF xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"; 
xmlns:rdfs="http://www.w3.org/2000/01/rdf-schema#"; 
xmlns:dc="http://purl.org/dc/elements/1.1/";>
<xsl:variable name="identifier">
  <xsl:value-of select="normalize-space(dc:identifier)"/>
</xsl:variable>
 <rdf:Description>
	<xsl:attribute name="rdf:about"><xsl:value-of 
select="$identifier"/></xsl:attribute>
                <rdf:type rdf:resource="http://purl.org/gem/qualifiers/GEM2"/>
                        <xsl:apply-templates select="dc:identifier"/>
....
 </rdf:Description>
</rdf:RDF>    
</xsl:template>
<xsl:template match="dc:identifier"> 
 <dc:identifier rdf:resource="{normalize-space(.)}"/> 
</xsl:template> 
		...
Thanks for any tips how to improve performance..

Cheers,
Ryan

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