Following the solution in the
faqs i thought this would work:
<xsl:value-of select="replace(.,'"',''')"/>
No, after it has been through the xml parser that is the XPath
expression
replace(.,'"',''')
and that last term is a syntax error, you need the XPath expression
replace(.,'"',"'")
which may be put into an XML attribute like so:
<xsl:value-of select="replace(.,'"',"'")"/>
David
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