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[xsl] Namespace 'http://www.w3.org/2005/xpath-functions' does not contain any functions (was Re: [xsl] XSL cant check if "File exists"?)

2006-08-29 14:04:48
Thanks Mukul.
I did try
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2006/xpath-functions";>
.........
                <xsl:if test="fn:doc-available($url)"><br /> da file
does not exists</xsl:if>
..........

 but IE says Namespace
'http://www.w3.org/2006/xpath-functions' does not
contain any functions.(tried both 2006 and 2005 in the
fn namespace declaration)
Firefox says "Error during XSLT transformation: An
unknown XPath extension function was called."

Am I missing something in the headers or should I just
wait until the Candidate recommendation is implemented
by most tool vendors?
If so, is there an immediate solution for this (to
check if a file exists)?
Thanks again,
-Tulaky
------------
Date: Mon, 28 Aug 2006 14:28:58 +0530
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
From: "Mukul Gandhi" <gandhi(_dot_)mukul(_at_)gmail(_dot_)com>
Subject: Re: [xsl] XSL cant check if "File exists"?
Message-ID: 
<7870f82e0608280158y191f54dcy9ae829ec63ca22ac(_at_)mail(_dot_)gmail(_dot_)com>

With XSLT 2.0, you can use the doc-available(string?
$uri) function.

On 8/28/06, Laky Tang <tulaky(_at_)yahoo(_dot_)com> wrote:
I have followed various postings and I am led to
believe that XSL does not have any built in
capability
to check if a file exists or not. I read there is a
way to check using extensions, but the following
example gives me an error "Namespace 'java.io.File'
does not contain any functions" in IE and XML spy.
It
works incorrectly in Firefox / Flock by always
saying
the file does not exist (even if it does). Changing
XSLT 1.0 to 2.0 did not make any difference.
I find it quite ironic that XSLT lacks this basic
capability to check if a file exists-or-not given
its
main use is in working with XML documents (and
files).
If there is a simple way to gracefully handle the
condition, can somebody please point me in the right
direction?
Thanks,
-Tulaky
Example adapted from another posting:
------------------------
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:fn="http://www.w3.org/2005/02/xpath-functions";

xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes";
xmlns:xlink="http://www.w3.org/1999/xlink";

xmlns:h="http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd";>
<!-- my other templates go here which call this with
the filename-->
<xsl:template name="file_exists"
xmlns:file="java.io.File">
 <xsl:param name="filename" />

 <xsl:if test="not(file:exists($filename))">
 file <xsl:value-of select="$filename"/> does not
exist!
 </xsl:if>
</xsl:template>
</xsl:stylesheet>

-- 
Regards,
Mukul Gandhi

http://gandhimukul.tripod.com

------------------------------



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