Many thanks, that was what I needed. :-)
//Pelle
----- Original Message -----
From: "Florent Georges" <darkman_spam(_at_)yahoo(_dot_)fr>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, August 30, 2006 1:57 AM
Subject: Re: [xsl] XPath location problem
You can use the following-sibling axis:
> cat per.xml
<animal>
<species>
<name language="English">Wolf</name>
<name language="Spanish">Lobo</name>
<name language="English">Warg</name>
<name language="Latin">Canis Lupus</name>
<name language="French">Loup</name>
</species>
</animal>
> cat per.xsl
<xsl:transform
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="2.0">
<xsl:output indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates select="animal/species"/>
</xsl:template>
<xsl:template match="species">
<xsl:variable name="second"
select="name[(_at_)language eq 'English'][2]"/>
<new>
<xsl:copy-of select="
$second, $second/following-sibling::name"/>
</new>
</xsl:template>
</xsl:transform>
> gexslt per.xsl per.xml
<?xml version="1.0" encoding="UTF-8"?>
<new>
<name language="English">Warg</name>
<name language="Latin">Canis Lupus</name>
<name language="French">Loup</name>
</new>
Regards,
--drkm
p4.vert.ukl.yahoo.com uncompressed/chunked Tue Aug 29 23:13:38 GMT 2006
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