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Re: [xsl] function for getting filename

2006-09-01 03:15:47
On 9/1/06, Frank Marent <frank(_dot_)marent(_at_)emnemics(_dot_)ch> wrote:
i'm struggling again and again over this point:

is there a function in xslt that gives me the clean filename of the
processed xml file? like

   'myfile.xml'
   'test.xml'
   'anyfilename.xml'

i do *not* need the document-uri. only the filename of the current
processed xml file.

In xslt 2.0 I use:

tokenize(base-uri(.), '/')[last()]

In xslt 1.0 you'll need to pass it in as a parameter.

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