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Re: [xsl] Sort before paging

2006-09-01 14:17:08
I'm  testing your advice but it doesnt works.

The xsl file is the following:

I'm trying to apply the template without any paging:

<?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; >

<xsl:output method="html" indent="yes"/>


<xsl:template match="/">
<xsl:call-template name="positionfilter"> 
<xsl:with-param name="sortedlist">
<xsl:for-each
select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL
ist/Outward" >
<xsl:sort select="Price/amount" data-type="number" order="ascending" />
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:with-param>
</xsl:call-template/>
</xsl:template>



<xsl:template name="positionfilter">
<xsl:param name="sortedlist"/>
<xsl:for-each select="msxsl:node-set($sortedlist)/">
<xsl:text>test</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>  

The error is still the same:

Not well formed and so on...


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