Hello Abel, thank you for the fast answer.
I am sending my XML and XSL for the list (I don't know it goes if).
I wanted that each it paginates of results he/she had an ordination.
But usually in my tests when I ask to order he orders everything, not
just the results of the page.
Regards,
Carlos H.
XML
-----------------------------------------------------------------
<?xml version="1.0" encoding="ISO-8859-1" ?>
<tribunais>
<tribunal>
<id>14</id>
<numero>1</numero>
<categoria>Tribunal Superior</categoria>
<nome>Superior Tribunal de Justiça</nome>
<website>www.stj.gov.br</website>
</tribunal>
<tribunal>
<id>2</id>
<numero>2</numero>
<categoria>Tribunal Superior</categoria>
<nome>Supremo Tribunal Federal</nome>
<website>www.stf.gov.br</website>
</tribunal>
<tribunal>
<id>16</id>
<numero>3</numero>
<categoria>Tribunal Superior</categoria>
<nome>Tribunal de Contas da União</nome>
<website>www.stm.gov.br</website>
</tribunal>
<tribunal>
<id>19</id>
<numero>4</numero>
<categoria>Tribunal Regional do Trabalho</categoria>
<nome>01ª Região - RJ</nome>
<website>www.trtrio.gov.br</website>
</tribunal>
<tribunal>
<id>20</id>
<numero>5</numero>
<categoria>Tribunal Regional do Trabalho</categoria>
<nome>02ª Região - SP</nome>
<website>www.trt02.gov.br</website>
</tribunal>
<tribunal>
<id>18</id>
<numero>6</numero>
<categoria>Tribunal de Contas </categoria>
<nome>Goiás</nome>
<website>www.tce.go.gov.br</website>
</tribunal>
<tribunal>
<id>17</id>
<numero>7</numero>
<categoria>Tribunal de Contas </categoria>
<nome>Bahia</nome>
<website>www.tce.ba.gov.br</website>
</tribunal>
<tribunal>
<id>15</id>
<numero>8</numero>
<categoria>Tribunal de Contas </categoria>
<nome>Alagoas</nome>
<website>www.tc.al.gov.br</website>
</tribunal>
</tribunais>
XSL
-----------------------------------------------------------------
<?xml
version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:msxsl="urn:schemas-microsoft-com:xslt" extension-element-prefixes="msxsl"
version="1.0">
<xsl:output method="xml" indent ="yes"/>
<xsl:param name="direcao"></xsl:param>
<xsl:param name="sortBy"></xsl:param>
<xsl:param name="start" select="1"/>
<xsl:param name="range" select="2"/>
<xsl:variable name="tableData">
<xsl:apply-templates select="tribunais/tribunal[position() >=$start and position()
< $start + $range]" mode="tableData">
</xsl:apply-templates>
</xsl:variable>
<xsl:template match="tribunais">
<table width="100%" border="1">
<tr align="center">
<td><a href="#"
onclick="renderData('categoria');">categoria</a></td>
<td><a href="#"
onclick="renderData('nome');">nome</a></td>
<td><a href="#"
onclick="renderData('website');">website</a></td>
</tr>
<xsl:apply-templates select="msxsl:node-set($tableData)/tribunal">
<xsl:sort select="*[name()=$sortBy]"
order="{$direcao}"/>
</xsl:apply-templates>
</table>
</xsl:template>
<xsl:template match="tribunal">
<tr>
<td><xsl:value-of select="categoria"/></td>
<td><xsl:value-of select="nome" /></td>
<td><xsl:value-of select="website" /></td>
</tr>
</xsl:template>
<xsl:template match="tribunal" mode="tableData">
<xsl:copy>
<xsl:copy-of select="categoria"/>
<xsl:copy-of select="nome"/>
<xsl:copy-of select="website"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
--------------------------------------------------------------------
Abel Online escreveu:
Hi Carlos,
It would help if you'd send us the XML you are trying to transform,
and the XSLT that you have got so far. Also, it'll help if you include
the XML of what you expect from your transformation (well, perhaps you
don't even want XML as output? Your post doesn't say).
Please update, it will make it easier to help you.
Kind regards,
Abel Braaksma
http://abelleba.metacarpus.com
Carlos Humberto - IntelVision wrote:
Hello it would like a help of you. I am then Brazilian they excuse
for my bad English. I would Like to paginate the data of a simple
XML through XSL and to order the results of each it paginates. could
anybody help me with some example? I already tried of everything and
I didn't get. I thank the help of all. Thank you, Carlos H
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