When I copy it using the following xsl template the xmlns:xs reference
is missing.
If you had copied the element the namespaces woul dhave been copied, but
instead you generated (using xsl:element) a new element of the sam
ename. (The main reason for using xsl:element in this way is to _avoid_
copying namespaces when that is needed:-)
Don't use
<xsl:element name="elem">
use
<xsl:copy>
similarly instead of
<xsl:attribute name="xsi:type"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<xsl:value-of select="@xsi:type"/>
</xsl:attribute>
You could use
<xsl:copy-of select="@xsi:type"/>
actually in this case, since you are also copying the content you can
just copy the whole node:
<xsl:template match="elem">
<xsl:copy-of select="."/>
</xsl:template>
David
--~------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--