On 9/8/06, Steve <subsume(_at_)gmail(_dot_)com> wrote:
Posted yesterday, but I isolated the problem significantly =)
The snippet below attempts to split the string 'mileage 6' into
[mileage] and [6] and then store it in $miles (for example).
I am trying to get the SUM of the resulting SPLIT of the nodes that
match 'mileage'.
I am close. Right now I only get one node, not the sum of all matches.
<xsl:variable name="miles">
<xsl:call-template name="str-split-to-words">
<xsl:with-param name="pStr"
select="msxsl:node-set($expenses[substring(expense,1,7)='mileage']/expense)"
/>
<xsl:with-param name="pDelimiters" select="' '" />
<!-- splitting expense at blank spaces -->
</xsl:call-template>
</xsl:variable>
<xsl:value-of select="msxsl:node-set($miles)/*[2]" /><br />
====
$expenses example:
<Expenses>
<expense>Mileage 6</expense>
<expense>cheese</expense> (wouldn't match)
<expense>Mileage 10</expense>
</Expenses>
====
Desired value of $miles: 16.
With FXSL2.0 one would simply write:
sum(f:map(f:compose(f:decimal(),
f:flip(f:substring-after(),' ')
),
/*/*[contains(.,' ')]
)
)
Or simply use the f:transform-and-sum() function:
f:transform-and-sum(f:flip(f:substring-after(),' '),
/*/*[contains(.,' ')]
)
In XSLT 1.0, one can use the "transform-and-sum" template of FXSL 1.x
--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
Thanks a bunch,
-Steve
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