<xsl:template match="/">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="address">
<address>
<xsl:apply-templates select="child::*[1]" />
</address>
</xsl:template>
<xsl:template match="*[not(local-name() = 'address')][parent::*[local-name() =
'address']]">
<xsl:variable name="elmnt-name">US_<xsl:value-of select="local-name()"
/></xsl:variable>
<xsl:element name="{$elmnt-name}">
<xsl:value-of select="." />
</xsl:element>
<xsl:apply-templates select="following-sibling::*[1]" />
</xsl:template>
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Senthilkumaravelan Krishnanatham <senthil(_at_)apple(_dot_)com>
Sent: Wed, 13 Sep 2006 18:00:01 -0700
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Element name Change for a node
Hi All,
I have the following structure in my XML and I want to transform this
all "address" node content to prefix with "US".
Please let me how to create the XSL template for the given input.
Input
<address>
<streetAddress>123 First Street</streetAddress>
<city>Sometown</city>
<state>CA</state>
<zip>12345</zip>
<province />
<country>USA</country>
</address>
output
<address>
<US_streetAddress>123 First Street</US_streetAddress>
<US_city>Sometown</US_city>
<US_state>CA<US_/state>
<US_zip>12345</US_zip>
<US_province />
<US_country>USA</US_country>
</address>
I do not know how to create the XSL for it to transform.
Thanks for your help.
Regards,
Senthil
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