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Re: [xsl] Grouping the elements

2006-09-14 06:25:51
Mukul Gandhi wrote:

   <xsl:template match="/Root">
        <Root>
            <xsl:for-each select="*[generate-id() =
generate-id(key('x', local-name())[1])]">

Hi Mukul, this was what I was looking for in my solution, but couldn't get right. Humbly updating my solution with yours, gives the following, making it better looking than the original:

<xsl:key name="x" match="Root/*" use="local-name()" />

<xsl:template match="Root">
   <xsl:copy>
       <xsl:apply-templates
        select="*[generate-id() =
           generate-id(key('x', local-name())[1])]"/>
   </xsl:copy>
</xsl:template>

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