Sounds like you are missing the parameter declaration
<xsl:param name="buildingDataFile"/>
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Tracey Zellmann [mailto:tracey(_dot_)zellmann(_at_)comcast(_dot_)net]
Sent: 17 September 2006 19:57
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] using a parameter to modify part of the
file path in document(...) function
Thanks.
However, I can not quite get it to work. I must be doing
something wrong.
I have this in my transformer set-up:
transformer.setParameter("buildingDataFile",
this.buildingDataName); where this.buidingDataName is "TownHouseData"
Then, in my style sheet I have, as you suggested,
<xsl:variable name="list" select="document(concat('../',
$buildingDataFile, '/inputXML/storyPages.xml'))"/>
However, I get this error message, stating that the variable,
$buildingDataFile has not been declared.
Error at xsl:variable on line 15 of
file:///C:/Documents%20and%20Settings/Tracey/workspace/Library
Project/xslt/stories.xsl:
XPST0008: XPath syntax error at char 40 on line 15 in {...le,
'/inputXML/storyPages.x...}:
Variable $buildingDataFile has not been declared
In other cases, I have been able to make use of transformer
parameters into the html part of astylesheet with something
like this:
<li><a href="../index.html" title="{$buildingTitle}"> , where
buildingTitle was a transformer parameter, but, as I said
before, whenever I try to get a parameter into a quoted
function, I get into trouble.
What am I missing?
There is a more going on in the stylesheet, but nothing
really before this line, so I haven't included it.
----- Original Message -----
From: "Michael Kay" <mike(_at_)saxonica(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Sunday, September 17, 2006 3:23 AM
Subject: RE: [xsl] using a parameter to modify part of the
file path in
document(...) function
Change your call on document() to
document(concat('../', $buildingDataFile,
'/inputXML/buildingStories.xml'))
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Tracey Zellmann [mailto:tracey(_dot_)zellmann(_at_)comcast(_dot_)net]
Sent: 16 September 2006 20:09
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] using a parameter to modify part of the
file path
in document(...) function
I am using XSLT 2.0 and JAVA 1.5.0_07 and the Saxon B
net.sf.saxon.TransformerFactoryImpl Transformer.
In my style sheet, I currently import an xml document
<xsl:variable
name="list"
select="document('../inputXml/storyPages.xml')"/>
Now that everything works, I want to change my input file
arrangements and use different documents, each named
storyPages.xml,
but from different directories.
examples:
../TownHouseData/inputXML/buildingStories.xml
../MiddlesexHotelData/inputXML/buildingStories.xml
../DamonMillData/inputXML/buildingStories.xml
and so forth.
I can set a parameter in my java program,
transformer.setParameter("buildingDataFile", "TownHouseData");
and use a different setting for the other buildings.
My problem is that I always get confused in XSLT using
variables and
parameters inside double and single quoted strings.
What is a clean syntax for accomplishing this?
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