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RE: [xsl] outputting <?xml version="1.0" encoding="UTF-8"?>

2006-09-18 07:36:33
This was one of the things I tried out before trying the list. My
current header is:

<xsl:output method="xml" version="1.0" encoding="UTF-8"
omit-xml-declaration="no"/> 

But it doesn't seem to have had the effect it should have done. I
suspect the dotnet xsl.transform lib I am calling has some option which
overrides this but I can't find it.

Ian Murphy
Integra XP
http://www.integra-xp.com
00 34 94 621 5265
 

-----Mensaje original-----
De: Abel Braaksma [mailto:abel(_dot_)online(_at_)xs4all(_dot_)nl] 
Enviado el: lunes, 18 de septiembre de 2006 13:52
Para: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Asunto: Re: [xsl] outputting <?xml version="1.0" encoding="UTF-8"?>

Ian Murphy wrote:
Now the question is, who is responsable for putting this header in 
place? From what I know it should be the .net 1.1 xsl libraries I use 
to do the transform, no? I've been searching the docs and can't find 
any reference to enabling or disabling the production of this header, 
though I could be looking for the wrong thing.
  

I missed on the whole discussion, but to enable/disable the <?xml ...?>
header part, you can do the following:

<xsl:output indent="yes" method="xml"  encoding="UTF-8" 
omit-xml-declaration="no" />

But, if you haven't got this statement *and* your method is "xml", the
default value for "omit-xml-declaration" is "no", meaning, that the XML
declaration, by default, should be output by the processor. Setting it
to "yes" will suppress the output of the xml declaration.

Abel Braaksma
http://abelleba.metacarpus.com

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