The problem is not with the template. In HTML, <br> is the correct form. If you
want <br/>, then you want your output to be XHTML. You'll have to change the
output method from HTML to XHTML:
e.g.,
<xsl:output method="XHTML" />
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Dharshana S Van Der Bona <dharshanav(_at_)yahoo(_dot_)com>
Sent: Tue, 19 Sep 2006 07:25:32 -0700 (PDT)
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] extracting HTML elements from document created by saxon:parse
Hi All,
I'm suing the following template to extract all the html tags that is not <a>
in to the xsl output.
<xsl:variable name="htmlContent" select="saxon:parse(concat('<!DOCTYPE tag
[<!ENTITY nbsp '' ''>]>',concat(concat('<tag>',text()),'</tag>')))"/>
<xsl:apply-templates select="$htmlContent" />
<xsl:template match="tag/*[name() != 'a']" >
<xsl:element name="{name()}">
<xsl:copy-of select="@*|text()|node()"/>
</xsl:element>
</xsl:template>
But it is not properly extracting tags such as <br/> and only outputs <br>
Is there a way to fix this?
Also is there a way to get around the parser complaints of not declared
exception?
Thanks,
Dharshana
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