Re: [xsl] Problem with ampersands

andrew welch wrote:
> If you really must deliver XML with the entities in place I would
> suggest using a placeholder element (eg <entityA/>) to represent it in
> the output and the post process the result with a suitable language to
> replace the placeholder elements with the entity references.
This would probably the best way to go with this problem. However how do 
i go about replacing all the occurrences of the entity equivalent with 
an element? Is this method the right approach?
<xsl:function name="f:replace-all">
   <xsl:param name="input" as="xs:string"/>
   <xsl:param name="words-to-replace" as="xs:string*"/>
   <xsl:param name="replacement" as="xs:string*"/>
   <xsl:sequence select="if (exists($words-to-replace)) then 
f:replace-all(replace($input, $words-to-replace[1], 
$replacement[1]),remove($words-to-replace,1),remove($replacement,1)) 
else $input"/>
</xsl:function>
<xsl:output method="xml" encoding="UTF-8" use-character-maps="brillMaps"/>
<xsl:template match="/">
   <xsl:variable name="str" select="'&#x0386; &amp; test test the quick 
brown fox text&#x0063;&#x0332;&#x0068;&#x0332;&#x006B;&#x0332;text test 
test the quick brown fox'"/>
   <xsl:variable name="replacementStr" as="xs:string*" 
select="$entityTable/search[matches($str,.)]/following-sibling::replace/concat('&#x3c;entity 
name=&#x22;',.,'&#x22;/&#x3e;')"/>
   <test>
       <xsl:value-of 
select="f:replace-all($str,$entityTable/search[matches($str,.)],$replacementStr)"/>
   </test>
</xsl:template>

Wherein, i have a character map with this values:

<xsl:output-character string="&#x3c;" character="&#x3c;"/>
<xsl:output-character string="&#x3e;" character="&#x3e;"/>

Thanks,
-- Jeff



--~------------------------------------------------------------------
XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--~--