There's no standard facility in XSLT 1.0 to produce multiple output files.
You can do it in 2.0 using xsl:result-document, or some 1.0 processors have
a vendor extension.
In 1.0, the only way to do this is to invoke the stylesheet once for each
output file, supplying a parameter to indicate which output file to generate
on that run.
Michael Kay
http://www.saxonica.com/
-----Original Message-----
From: Thangavelu Srinivasan [mailto:vasantry(_at_)gmail(_dot_)com]
Sent: 27 September 2006 06:34
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Break output into files based on values
Hi All,
I need help in resolving the problem for the below. I am
using XSLT 1.0.
Any suggestions are welcome.
My XML:
<root>
<DataComponent id="one">
<DatasComponent>
<p>This is a sample text</p>
</DatasComponent>
</DataComponent>
<DataComponent id="two">
<DatasComponent>
<p>This is a sample text</p>
</DatasComponent>
</DataComponent>
<DataComponent id="three">
<DatasComponent>
<p>This is a sample text</p>
</DatasComponent>
</DataComponent>
</root>
Result I am Expecting:
Based on the id, it has save in the folder as a individual
xml file with their content.
Filename: one.xml
<DataComponent id="one">
<DatasComponent>
<p>This is a sample text</p>
</DatasComponent>
</DataComponent>
Filename: two.xml
<DataComponent id="two">
<DatasComponent>
<p>This is a sample text</p>
</DatasComponent>
</DataComponent>
My XSL:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="doc" />
<xsl:template match="DataComponent">
<xsl:apply-templates>
</xsl:template>
</xsl:stylesheet>
Thanks,
Srinivas
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