Re: [xsl] create escaped(?) html of some nodes

This template

<xsl:template match="Para">
 <p><xsl:apply-templates /></p>
</xsl:template>

will change all
<Para>xx</Para> to
<p>xx</p>

I am sorry, I don't know the answer to your 2nd question. Just
curious, why do you want <p> to appear as &lt;p&gt; in the output?

On 10/9/06, Jan Limpens <jan(_at_)limpens(_dot_)com> wrote:
> Mukul,
>
> thanks for the quick reply. Unfortunately this seems to change almost
> nothing at all (only the document element's attributes order changed a bit).
> While the idea seems good, the second template never matches better than
> the first and thus does not seem to be called.
>
> And then, how can I do the escaping part, so that a <p> becomes a
> &lt;p&gt; ?
>
> Jan
>
> Mukul Gandhi schrieb:
> > It seems a modified identity transform will work.
> >
> > <xsl:template match="node() | @*">
> >   <xsl:copy>
> >       <xsl:apply-templates select="node() | @*" />
> >   </xsl:copy>
> > </xsl:template>
> >
> > <xsl:template match="Para">
> >   <p><xsl:apply-templates /></p>
> > </xsl:template>


--
Regards,
Mukul Gandhi

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