[xsl] Rename Some Node ans attribute

Hi to all

I need to change this xml:
<soapenv:Envelope 
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"; 
xmlns:ser="http://services.standardcup.esel.it";>
  <soapenv:Body>
     <ser:RICHIESTA_PRESTAZIONI_EROGABILI DataOra="10102005" idCup="1" 
idOperatore="1"/>
  </soapenv:Body>
</soapenv:Envelope>

into this:

<soapenv:Envelope 
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/"; 
xmlns:ser="http://regione.campania.it/schemas/cup";>
  <soapenv:Body>
     <ser:ELENCO_PRESTAZIONI DataOra="?" idCUP="?" idOperatore="?">
        <ser:PRESTAZIONE/>
         
      
     </ser:ELENCO_PRESTAZIONI>
  </soapenv:Body>
</soapenv:Envelope>

Pay attention on idCup that must be idCUP on the trasformation: i have 
this fot do it:
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; 
xmlns="http://services.standardcup.esel.it"; 
xmlns:cup="http://services.standardcup.esel.it";>
   <xsl:strip-space elements="*"/>
   <xsl:output indent="yes"/>
   <!--
most stuff you want to copy:
-->
   <xsl:template match="*">
     
      <xsl:copy>
           <xsl:copy-of select="@*[name()!='idCup']"/>
           <xsl:if test="@idCup">
                   <xsl:attribute name="idCUP">
                       <xsl:value-of select="@idCup">
                       </xsl:value-of>
                   </xsl:attribute>
           </xsl:if>
           <xsl:apply-templates/>
       </xsl:copy>
   </xsl:template>
  

</xsl:stylesheet>

Many thanks.

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