[xsl] Select one from Multiple Values and Order Values

Hello,

I need to select the URL value from multiple values in dc:identifier in a 
xml record as a base identifier (rdf:Description rdf:about). And I need to 
represent all dc:identifier values in a rdf file with the order of http URL 
value first.
For example, here is my xml document.

<dc:identifier>AJ-097</dc:identifier>
<dc:identifier>TMK2534</dc:identifier>
<dc:identifier>http://content.wisconsinhistory.org/u?/aj,71</dc:identifier>

And here is my expected rdf document.
<rdf:Description rdf:about="http://content.wisconsinhistory.org/u?/aj,71";>
                <rdf:type rdf:resource="http://purl.org/gem/qualifiers/GEM2"/>
                
<dc:identifier>http://content.wisconsinhistory.org/u?/aj,71</dc:identifier>
                                <dc:identifier>AJ-097</dc:identifier>
                                <dc:identifier>TMK2534</dc:identifier>

I tried to handle this. But, kind of stuck now.

Could you give some advice?

Here is my xslt.

<xsl:template match="oai_dc:dc">
     <xsl:variable name="identifier">
         <xsl:if test="http">  <xsl:value-of 
select="normalize-space(dc:identifier)"/> </xsl:if>
     </xsl:variable>
<rdf:Description>
      <xsl:attribute name="rdf:about"><xsl:value-of 
select="$identifier"/></xsl:attribute>
     <rdf:type rdf:resource="http://purl.org/gem/qualifiers/GEM2"/>
                <xsl:apply-templates select="dc:identifier"/>
 </rdf:Description>
</rdf:RDF>
</xsl:template>

<xsl:template match="dc:identifier">
    <xsl:choose>
     <xsl:when test=". = 'http'">
           <dc:identifier><xsl:value-of 
select="normalize-space(.)"/></dc:identifier>
     </xsl:when>
     <xsl:otherwise>
           <dc:identifier><xsl:value-of 
select="normalize-space(.)"/></dc:identifier></xsl:otherwise>
     </xsl:choose>
</xsl:template>

Thanks a lot in Advance,

Best regards,
Ryan

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